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va rog rapid!
log in baza 2 din 4+log in baza 4 din 8+log in baza 8 din 16+log in baza 16 din 32!


Răspuns :

[tex] log_{2}(4) + log_{4}(8) + log_{8}(16) + log_{16}(32) [/tex]

[tex] = log_{2}( {2}^{2} ) + log_{ {2}^{2} }( {2}^{3} ) + log_{ {2}^{3} }( {2}^{4} ) + log_{ {2}^{4} }( {2}^{5} ) [/tex]

[tex] = 2 log_{2}(2) + \frac{3}{2} log_{2}(2) + \frac{4}{3} log_{2}(2) + \frac{5}{4} log_{2}(2) [/tex]

[tex] = 2 \times 1 + \frac{3}{2} \times 1 + \frac{4}{3} \times 1 + \frac{5}{4} \times 1[/tex]

[tex] = 2 + \frac{3}{2} + \frac{4}{3} + \frac{5}{4} = \frac{24 + 18 + 16 + 15}{12} = \frac{73}{12} [/tex]