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Stiind ca a×b=75,iar [a,b]=5,atunci(a,b)

Răspuns :

avem formula.[a.b]×(a.b)=a×b
inlocuim...
5×(a.b)=75
(a.b)=75÷5=15
[, a, b] =5 => a/5> a = 5*y
b/5 >b=5*x
5y*5x=75/:5
y*x = 15
y=*3,5,15,1
x=5,3,1,15
Cazul 1 - y=3,x=5=>a=3*5=15 b=5*5=25 cazul 2 si invers a= 25, b=15
Cazul 3 y=15,x=1 => a= 15*5 =75, b=1*5=5
Cazul 4 -invers a=5,b=75