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Calculati: [0,(3)+1,(3):1 7supra9]:(1+ 1supra12) Please!!

Răspuns :


[tex]( 0.(3) + 1.(3) \div \frac{17}{9} ) \div (1 + \frac{1}{12} ) = \\ ( \frac{1}{3} + \frac{12}{9} \times \frac{9}{17} ) \div ( \frac{12}{12} + \frac{1}{12} ) = \\ ( \frac{1}{3} + \frac{12}{17} ) \div \frac{13}{12} = \frac{17 + 36}{52} \times \frac{12}{13} = \\ \\ \frac{53}{52} \times \frac{12}{13} [/tex]