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un compus monobromurat X contine: 40,81% C, 4,76% H si 54,42% Br. Aflati formula moleculara a compusului.

Răspuns :

C=40,81/12=3,40: 0,685=

H=4,76/1=4,76:0.68=7

Br=54,42/80=0.68:0,68=1

C5H7Br