1.
MH2SO4=2+32+4.16=98
MCaCO3=40+12+3.16=100
MHNO3=1+14+3.16=63
MNaOH=23+16+1=40
MMgO=24+16=40
MH3PO4=3+31+4.16=98
MSO2=32+2.16=64
MMg(OH)2=24+2.16 +2=58
2.
180 g H2O se aplica formula : n=m : M [ n=nr.moli]
moli H2O n= 180 g : 18g/moli=10 moli H2O
3.
n=196 g : 98g/moli=2 moli H2SO4
4.
se aplica formula n=m : M
m=n.M
m=5 moli .64g/moli=320 g SO2
5.
m=6moli .17 g/moli= 102 g NH3
MNH3=14+3=17----->1mol=17g
