a/5 = (b+2)/12 = (c+3)/8 = k. De aici rezulta:
a = 5k
b+2 = 12k, adica b = 12k-2
c+3 = 8k, adica c = 8k-3
Dar a+b+c = 95, inseamna ca:
5k + 12k - 2 +8k - 3 = 95
25k = 95 + 2 + 3
25k = 100
k = 4
Acum putem calcula:
a = 5k = 20
b = 12k-2 = 48 - 2 = 46
c = 8k-3 = 29