26,88 L CO2__________ a g C
22,4 L CO2 ___________ 12 g C
=> a = 26,88x12/22,4 = 14,4 g C
21,6 g H2O___________ b g H
18 g H2O_____________2 g H
=> b = 21,6x2/18 = 2,4 g H2
=> 21,6 - 14,4 - 2,4 = 4,8 g O
=> d(oxigen) = M.molec. (subst.) / M.molec. O2
=> M.molec.(subst.) = d(oxigen)xM.molec.O2 = 2,25x32 = 72 g/mol
=> la 21,6 g subst. .... 14,4 g C..... 2,4 g H .... 4,8 g O
la 72 .......................... c C ............ d H ........ e O
=> c = 72x14,4/21,6 = 48 g C , d = 72x2,4/21,6 = 8 g H , e = 72x4,8/21,6 = 16 g O
=> C = 48/12 = 4 at C
H = 16/1 = 8 at H
O = 16/16 = 1 at O
=> C4H8O => CH3-O-CH2-CH2-CH3 = metilpropileter
CH3-CH2-CH2-CH=O = butanaldehida (aldehida buririca)
