Problema 505, va rog!

CnH2n-7NH2 + HI => CnH2n-7NH3]+I- sarea cuaterrnara de iodura de arilamoniu
=>
100% substanta.........................6,33% N
14n+137....................................... 14 g N
=> 1400 = 6,33(14n+137)
=> n = 6
=> C6H5NH3I adica C6H8NI
=> raspuns C.