Va roggggg ,dau coroana !!!!!!

CM≡AB ⇒ CM≡BC (deoarece ABCD patrat) ⇒ΔCBM isoscel ⇒ m(∡CBM)≡m(∡BMC)
m(∡CBM)+m(∡BMC)=180°-135°
m(∡CBM)+m(∡BMC)=45°
m(∡CBM)=45°:2
m(∡CBM)=22,5° (sau 22°30')
m(∡BMC)=22,5°
m(∡ABM)=m(∡ABC)+m(∡CBM)=90°+22,5°=112,5° (sau 112°30')