135 g... md............................n moli
Mg + 2HCl => MgCl2 + H2
24..........2x36,5.....................1
n = 135/24 = 5,625 moli H2
=> md = 2x36,5x135/24 = 410,625 g HCl
c% = mdx100/ms
=> ms = mdx100/c% = 410,625x100/36,5
=> ms = 1125 g sol HCl reactionata
5,625 moli.......m g......... md1
H2 + Cl2 => 2HCl
1..............2x35,5.......2x36,5
=> m = 2x35,5x5,625/1 = 399,375 g Cl2
md1 = 2x36,5x5,625/1 = 410,625 g HCl
ms1 = md1 + m.apa = 41,625 + 952,5 = 1363,125 g
c%1 = md1x100/ms1 = 30,12%