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calculati limita x-> inf (x-ln(x^2+x+1))

Răspuns :

lim x(1-ln(x^2+x+1)/x)

lim x(1- ln(x^2+x+1)/(x^2+x+1) × (x^2+x+1)/x )

s-a folosit lim x-> inf lnx/x=0

⇒∞×(1-0)= ∞


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Vezi imaginea C04F