ro = p = ms / Vs
=> ms = pxVs = 230 x 0,9 = 207 kg sol etanol
c% etanol = 20%, c% =mdx100/ms
=>md =msxc%/100 = 207x20/100 = 41,4 kg etanol
41,4 kg................................... md
CH3-CH2-OH + O2 => CH3-COOH + H2O
46 kg/kmol............................ 60 kg/kmol
=> md acid = 41,4x60/46 = 54 kg acid