CnH2n+2 + Br2 => CnH2n+1Br + HBr
=>
100% comp. halogenat___________ 73,4% Br
14n+81 _____________________ 81
=> 8100 = (14n+81)*73,4
=> 8100 - 5945,4 = 1027,6n
=> 2054,6 = 1027,6n
=> 2 = n
=> C2H5Br
CH3-CH2-Br = bromoetan (bromura de etil)
CH3-CH(Br)2 = 1,1-dibromoetan (bromura de etilen)
CH3-C(Br)3 = 1,1,1-tribromoetan (bromura de etilin)
CH2Br-C(Br)3 = 1,1,1,2-tetrabromoetan
CH(Br)2-C(Br)3 = 1,1,1,2,2-pentabromoetan
C(Br)3-C(Br)3 = 1,1,1,2,2,2-hexabromoetan
