md = msxc/100
=> md = 200x28/100 = 56 g KOH
n1 moli....56 g.......n2 moli
HCl + KOH => KCl + H2O
1.............56...............1
a) cati moli de acid s-au consumat
=> n1 = 1x56/56 = 1 mol HCl
b) cati moli de sare rezulta
n2 = 56x1/56 = 56 g KCl
c) care este masa de solutie de acid clorhidic
n = nr moli = masa / M.moleculara
M.moleculara HCl = 36,5 g/mol
=> m = 1 x 36,5 = 36,5 g HCl
=> md = 36,5 g HCl
ms = ?
c = 30%
=> ms = mdx100/c% = 36,5x100/30 = 121,67 g sol HCl