[tex]x = (-3\sqrt{2})^0 = 1\\y = (-3\sqrt{2})^{-1} = \frac{1}{-3\sqrt{2}} =-\frac{\sqrt{2} }{6} \\\frac{1}{y} +\frac{1}{x} =\frac{1}{-\frac{\sqrt{2} }{6}} +1 =1:-\frac{\sqrt{2} }{6}+1 =\\1*-\frac{6}{\sqrt{2} } + 1 = 1*-\frac{6\sqrt{2}}{2}+1 = - 3 \sqrt{2} +1[/tex]
