mx² -(3m-4)·x -6·(m-1)=0 => x₁+x₂=-b/a =3m+4 /m si x₁·x₂=c/a =-6m+6 /m .
(n-1)·x² -(n-1)·x +6·(n-2)=0 => x₁+x₂=-b/a =n-1 /n-1=1 si x₁·x₂=c/a =6n-12 /n-1 =>
3m+4 /m=1 => 3m+4=m => 2m=-4 => m=-2 de unde obtinem
-6m+6 /m=6n-12 /n-1 <=> 6/-2=6n-12 /n-1 <=> -3=6n-12 /n-1 => 6n-12=-3n+3 =>
9n=15 => n=5/3 . In concluzie m=-2 si n=5/3 .
