52 si 53 dau 20de puncte

52.
a+b+c=121
a:c=10 r 5 =>a=10c+5
b:c=5 r4 =>b=5c+4
Inlocuim in relatie: 10c+5+5c+4+c=121=>16c+9=121
16c=112=>c=112/16=7
a=70+5=75
b=35+4=39
a=75 , b=39 ,c=7
53.
a+b+c=135
a:c=12 r 1 =>a=12c+1
b:c=31 r 2=>b=31c+2
12c+1+31c+2+c=135=>44c+3=135=>c=132/44=3
b=31*3+2=95
a=12*3+1=37
a=37 , b=95 , c=3