200<n•45<2011
200<5•45; 200<225; (pt n=4 => 4•45=180<200)
44•45<2011; 1980<2011;
=> n∈{5, 6, 7, 8, ……., 44};
sunt 44-5+1=40 de elemente
200<n•18<2011
200<12•18; 200<216; (pt n=11 => 11•18=198<200)
111•18<2011; 1998<2011;
=> n∈{12, 13, 14, ……., 111};
sunt 111-12+1=100 de elemente
