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toate punctele de la exterior.10
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a) ab+bc+ca=10a+b+10b+c+10c+a=11a+11b+11c=11 ⇒ 11(a+b+c)=88 a+b+c=88:11=8
b) 11(a+b+c)=abc a+b+c=abc/11
c) 100a+10b+c+100c+10a+b+100b+10c+a=777 ⇒ 111a+111b+111c=777 111(a+b+c)=777 a+b+c=7
d) 10a+b+10a+c+10b+a+10b+c+10c+a+10c+b=110 ⇒ 22a+22b+22c=110 22(a+b+c)=110 a+b+c=110:22=5