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(2^38:2^10+6^23:6^13):[2^10×3^10+(2^14)^2]

Răspuns :

(2^28+6^10):(6^10+2^28)=1


a^x:a^y=a^(x-y)

a^x*a^y=a^(x+y)

(a^x)^y=a^(x*y)