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[tex]\it -\dfrac{3}{5} +0,2+(-\dfrac{6}{10}) + (+0,8) = -0,6+0,2-0,6+0,8=\\\\=(0,2+0,8)-(0,6+0,6) =1-1,2=-0,2\\\\If \ you\ want:\ \ -0,2= -\dfrac{\ 2^{(2}}{10}=-\dfrac{1}{5}[/tex]