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Determinati numerele abc stiind ca:
abc=ab×cb+c


Răspuns :

abc=ab•cb+c

ab0+c=ab•cb+c

=> ab0=ab•cb

sau ab•10=ab•cb

=> cb=10, deci c=1; b=0; a∈{1,2,3,......., 9}

abc∈{101,201,301,401,.....,901}