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[tex]\int\limits {\frac{1}{x-1} } \, dx[/tex]

Răspuns :

∫ 1/(x-1) dx= ln(x-1) +C

As simple as that.

[tex]\int\limits {\frac{1}{x-1} } \, dx = ln(x-1) + c , pentru ca [ln(x-1)]'= \int\limits {\frac{1}{x-1} } \, dx[/tex]