3/(x²-2x) ≥1
C.E ..x∈r\{0;2}
3≥(x²-2x)
x²-2x≤3
x²-2x-3≤0
f(x) =x²-2x-3 functie de grad 2
ecuiatia atasata
x²-2x-3=0 are radaciniole x1,2=(2+/-√(4+12))/2
x1=-1; x2=3
si are semnul " -" intre radacini
deci x∈[-1;3]
dar nu trebuiesa uitam sa eliminam valorile in care expresia nu e definita
dexci ras[puns final
x∈[-1;3]\{0;2}⇔x∈[-1;0)∪(0;2)∪(2;4]
