1/√2+1/√3>0
1/√2+1/√3=√2/2+√3/3=(3√2+2√3)/6
3√2+2√3 comparat cu 6
ridicam la patrat
18+12+12√5 compatrat cu 36
30+12√5 comparat cu 36
12√5>6
deci
3√2+2√3 > 6
deci (3√2+2√3)/6>1 adica 1/√2+1/√3>1
comparam pe
3√2+2√3 cu 12
ridicam la patrat
30+12√5 comparat cu 144
12√5 comparat cu114
2 radical 5 comparat cu 19 ridicam la patrat
deci
20<361
deci(3√2+2√3) /12 <1
(3√2+2√3 )/6<2
deci 1<1/√2+1/√3=(3√2+2√3 )/6 <2
atunci [1/√2+1/√3]=1
as complicated as that!!!
