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Sa se scrie primii 5 termeni ai sirurilor ([tex]x_{n}[/tex])[tex]n_\geq {1}[/tex] ; ([tex]y_{n}[/tex])[tex]n_\geq {1}[/tex] .

[tex]x_{n}[/tex] =[tex]\frac{3n^{2} -1 }{n^{2}+1}[/tex]


Răspuns :

x1=(3*1-1)/(1+1)=2/2=1

x2=(3*4-1)/(4+1)=11/5

x3= (3*9-1)/(9+1)=26/10=13/5

x4=(3*16-1)/(16+1)=47/17

x5=(3*25-1)/(25+1)=74/26