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Determinați numerele naturale consecutive ab si ac pentru care ab + ac=369

Răspuns :

ac=ab+1 ->

ab+ ab+1=369
2ab+1=369
2ab= 369 -1
2ab=368
ab=184

ac=ab+1
ac= 184 +1
ac=185

ab+ac=369

ac=ab+1

ab+ab+1=369

2ab+1=369

2ab=369-1

2ab=368

ab=368/2

ab=148

ac=2ab+1

ac=2*148+1

ac=296+1

ac=297