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Suma a trei numere naturale consecutive este 48.determinati nr

Răspuns :

a+a+1+a+2=48

3a+3=48

3a=48-3

3a=45

a=45:3=15

b=16

c=17


a+b+c=15+16+17=48

a+b+c=48

a,b,c-consecutive

48:3=16

b=16

a=16-1

b=16+1


a+b+c=48

a,b,c-consecutive

48:3=16

b=16

a=16-1

b=16+1