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calculaza [(147:7-5+3*4]:4-2012*0

Răspuns :

(21-5+12):4-2012×0=
(21-17):4-2012×0=
4:4-0=
1-0=1
[(147÷7-5+3×4)]÷4-2012×0=
=(21-5+12)÷4-0
=(16+12)÷4-0
=28÷4-0
=7-0
=7