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2015 la puterea 0 plus 3 la puterea a doua minus 2 la puterea 4 minus 4 la a doua plus 7 la puterea 2

Răspuns :


[tex] {2015}^{0} + {3}^{2} - {2}^{4} - {4}^{2} + {7}^{2} = 1 + {3}^{2} - {2}^{4} - {4}^{2} + {7}^{2} = 1 + 9 - 16 - 16 + 49 = 27 [/tex]