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De aflat Mr la:HCl,ClO,NH3,HF,BaO,Br2,CH4
Va rog urgent!!!


Răspuns :

[tex]M_{HCl}=A_{H}+A_{Cl}=1+35.5=36.5\ g/mol \\ \\  M_{NH_3}=A_{N}+(3*A_{H})=14+3=17\ g/mol \\ \\ M_{HF}=A_H+A_F=1+19=20\ g/mol \\ \\ M_{BaO}=A_{Ba}+A_O=137+16=153\g/mol \\ \\ M_{Br_2}=2*A_{Br}=2*80=160\ g/mol \\ \\ M_{CH_4}=A_C+(4*A_H)=12+4=16\ g/mol[/tex]