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Rezolvati va rog acest exercitiu
(2√3-7)²=?


Răspuns :

4×3-2×2 \sqrt{3}×7 +49
=12-28 \sqrt{3}+49
= 61-28 \sqrt{3}

(2√3-7)²=(2√3)²-2*2√3 *7+7²=4*3-28√3+49=12+49-28√3=61-28√3

as simple as that!!!

Obs: am tinut cont dedezvoltarea (a-b)² unde a=2√3 si b=7