[tex]2x + \frac{3}{9} - \frac{2}{3} \times (x + 2) = 2x - \frac{5}{18} + \frac{x}{6} \\ \\ \frac{3}{9} - \frac{2}{3}(x + 2) = - \frac{5}{18} + \frac{x}{6} \\ \\ \frac{1}{3} - \frac{2(x + 2)}{3} = - \frac{5}{18} + \frac{x}{6} \\ \\ \frac{1 - 2(x + 2)}{3} = - \frac{5}{18} + \frac{x}{6} \\ \\ \frac{1 - 2(x + 2)}{3} = \frac{x}{6} - \frac{5}{18} \\ \\ 2( - 2x - 3) = x - \frac{5}{3} \\ \\ - 4x - 6 = x - \frac{5}{3} \\ \\ - 6 = x - \frac{5}{3} + 4x \\ \\ - 6 = 5x - \frac{5}{3} \\ \\ - 6 + \frac{5}{3} = 5x \\ \\ - \frac{13}{3} = 5x \\ \\ - \frac{ \frac{13}{3} }{5} = x \\ \\ - \frac{13}{3 \times 5} = x \\ \\ - \frac{13}{15} = x \\ \\ x = - \frac{13}{15} [/tex]
