C₆H₆ + HO-NO₂ ⇒ C₆H₅-NO₂ + H₂O
C₆H₆ + 2HO-NO₂ ⇒ O₂N-C₆H₄-NO₂ + 2H₂O
C₆H₆ ⇒ C₆H₆
x moli -benzen , y-nitrobenzen,z-dinitrobenzen
x/y = 2/2 ⇒ y = 2x/2
x/z = 2/1 ⇒ z = x/2
m benzen = 1,56t = 1560kg
n benzen = 1560/78 = 20kmoli
x+y+z = 20 ⇔ x+2x/2 + x/2 = 20 ⇔ 5x/2 = 20 ⇔ 5x=40 ⇒ x = 8 kmoli
y = 8 kmoli, z = 4 kmoli
m nitrobenzen = 8×123 = 984kg
3. nC₆H₆/nHNO₃ = 8:16 = 1:2
n HNO₃ = y+2z = 8+2*4 = 16 kmoli