Rezolvare algebrica
a + b + c = 1 012
b = a / 2 + 40
c = 3 x a
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a + b + c = 1 012
a + ( a / 2 + 40 ) + 3 x a = 1 012
4 x a + a / 2 = 1 012 - 40 = 972
8 x a + a = 2 x 972
9 x a = 2 x 972
a = 2 x 972 / 9 = 2 x 108 = 216 → primul numar
b = 216 / 2 + 40 = 108 + 40 = 148 → al doilea numar
c = 3 x 216 = 648 → al treilea numar
216 + 148 + 648 = 1 012 → suma celor trei numere
Raspuns: 216; 148 si 648
