H2N-C6H4-COO-C2H5
H2N-C6H4-COOH + HO-C2H5 ⇄ ester + H2O
initial : n moli 10n moli
au reactionat : x x
la echilibru : (n-x) (10n-x) x x
x² / [(n-x)(10n-x)] = 5,3 0,188x² = 10n² - 11nx + x²
0,812x²- 11nx + 10n² = 0
x² - 13,546nx² + 12,315 = 0 x = 0,98n
η = 0,98n/(9,02n) · 100 = 10,864%
c) acid : 0,02n moli ; alcool : 9,02n moli ; ester : 0,98n; apa : 0,98n
n total = 11n
% acid = 2/11 = 0,18% % alcool = 902/11 = 82%
%ester = %apa = 98/11 = 8,91%