solutia finala de CH3-COOH : Vs = 100ml ms = 100g c = 5% ⇒ md = 5g
solutia initiala : msi = 5·100/80 = 62,5 g Vs = 62,5/1,07 = 5,84 ml
497.
C6H5-NH2 + NaNO2 +HCl ⇒ C6H5-N⁺≡N]Cl⁻ + NaOH
n anilina = n azotit
n azotit = 5·0,3/93 = 1/62 moli
solutia de azotit : md = 69·1/62 = 1,1129 g
ms = 111,29/5 = 22,258g