C6H5-C(CH3)=CH2 + 4 [O] => C6H5-C(CH3)=O + CO2 + H2O
2 KMnO4 + 3 H2SO4 => K2SO4 + 2 MnSO4 + 5 [O] + 3 H2O
M hc = 118.2 g/mol, m hc=5.2 g
n hidrocarbura = 0.044
1 mol de hc consuma 4 mol [O]
0.044 mol hc consuma a mol [O]
a= 0.176 mol [O]
asadar:
5 mol [O] se obtin din 2 mol permanganat
0.176 mol [O] se obtin din b mol permanganat
b=0.0704 mol KMnO4
C= n/V => V = n/C =>0.0704 mol/0.2(mol/L) =0.352 L sol. KMnO4 0.2M