Masa molara Fe3O4 = 56*3 + 16*4 = 168 + 64 = 232 g
%Fe in Fe3O4 = 168*100/232 (cp=md*100/ms)
=72. 413 %
Masa molara FeO = 56 + 16 = 72g
%Fe in FeO = 56*100/72
= 77. 77 %
Masa molara Fe2O3 = 56*2 + 16*3 = 112 + 48 = 160g
%Fe in Fe2O3 = 112*100/160 =70 %
=> cel mai mare procent de Fier il are FeO
Sper ca te-am ajutat !