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3x-2(20-x)=5x-8(12-x)+20=?

11-8y=13-3y=?

5(3z-5)+8=39


Răspuns :

3x-40+2x=5x-96+8x+20
5x-40=13x-76
5x-13x= -76+40
-8x= -36
x= 36/8
x=9/2

-8y+3y=13-11
-5y=2
y= -2/5

15z-25+8=39
15z-17=39
15z=39+17
15z=56
z=56/15
3 x - 2 ( 20 - x ) = 5 x - 8 ( 12 - x ) + 20
3 x - 40 + 2 x = 5 x - 96 + 8 x + 20 
5 x - 5 x - 8 x = - 76 + 40 
- 8 x = - 36 
x = ( - 36) : ( - 8) 
x = 9 / 2 = 4 intregi si 1 / 2 = 4,5

11 - 8 y = 13 - 3 y 
- 8 y + 3 y = 13 - 11 
- 5 y = 2 
y = - 2 / 5 

5 ( 3 z - 5 ) + 8 = 39
15 z - 25 + 8 = 39 
15 z = 39 + 17 
15 z = 56 
y = 56 /15