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se dau punctele A(1,3) B(3,-3) C(-5,1) .Calculati perimetrul triunghiului ABC

Răspuns :

[tex]A(1,3)[/tex]

[tex]B(3,-3)[/tex]

[tex]C(-5,1)[/tex]

[tex]AB=\sqrt{{(x_{B}-x_{A})}^{2}+{(
y_{B}-y_{A})}^{2}}[/tex]

[tex]AB=\sqrt{{(3-1)}^{2}+{(
- 3-3)}^{2}}[/tex]

[tex]AB=\sqrt{{2}^{2}+{(
- 6)}^{2}}[/tex]

[tex]AB=\sqrt{4+36}[/tex]

[tex]AB=\sqrt{40}[/tex]

[tex]AB=2\sqrt{10}[/tex]

[tex]AC=\sqrt{{(x_{C}-x_{A})}^{2}+{(y_{C}-y_{A})}^{2}}[/tex]

[tex]AC=\sqrt{{( - 5-1)}^{2}+{(1-3)}^{2}}[/tex]

[tex]AC=\sqrt{{( -6)}^{2}+{( - 2)}^{2}}[/tex]

[tex]AC=\sqrt{36+4}[/tex]

[tex]AC=\sqrt{40}[/tex]

[tex]AC=2\sqrt{10}[/tex]

[tex]BC=\sqrt{{(x_{C}-x_{B})}^{2}+{(y_{C}-y_{B})}^{2}}[/tex]

[tex]BC=\sqrt{{( - 5-3)}^{2}+{(1 + 3)}^{2}}[/tex]

[tex]BC=\sqrt{{( - 8)}^{2}+{4}^{2}}[/tex]

[tex]BC=\sqrt{64+16}[/tex]

[tex]BC=\sqrt{80}[/tex]

[tex]BC=4\sqrt{5}[/tex]

[tex]AB=AC=>\Delta \: ABC \:isoscel[/tex]

[tex]P=AB+AC+BC[/tex]

[tex]P=2AB+BC[/tex]

[tex]P=2AC+BC[/tex]

[tex]P=2 \times 2 \sqrt{10} + 4 \sqrt{5} [/tex]

[tex]P=4 \sqrt{10} + 4 \sqrt{5} [/tex]

[tex]P = 4( \sqrt{10} + \sqrt{5} )[/tex]