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a=3 , b=11 => calculati 7a-2b/2a+3b rapid va rog dau coroana la cel mai bun raspuns :]

Răspuns :

[tex]a = 3[/tex]

[tex]b = 11[/tex]

[tex] \frac{7a - 2b}{2a + 3b} = \frac{7 \times 3 - 2 \times 11}{2 \times 3 + 3 \times 11} = \frac{21 - 22}{6 + 33} = \frac{ - 1}{39} = - \frac{1}{39} [/tex]

[tex]21 - \frac{22}{3} + 33[/tex]
[tex] = 54 - \frac{22}{3} [/tex]
[tex] = \frac{140}{3} [/tex]