👤

calculati (√2-√3)^2-(√2-1)(√2+1)+√24

Răspuns :

[tex] {( \sqrt{2} - \sqrt{3} )}^{2} - ( \sqrt{2} - 1)( \sqrt{2} + 1) + \sqrt{24} [/tex]

[tex] = 2 - 2 \sqrt{6} + 3 - 2 + 1 + 2 \sqrt{6} [/tex]

[tex] = 4[/tex]