7.ΔABC
m(∡A)=90°
AD⊥BC
BD=2 cm
CD=8 cm
____________
AΔ=?
ΔABC
m(∡A)=90°}⇒conform teoremei inaltimii AD²=BD·DC
AD²=2 cm·8 cm
AD²=16 cm
AD=√16 cm
Ad=4 cm
AΔ=b·h/2⇒AΔ=10 cm·4 cm/2⇒AΔ=20 cm²
8. tg 60°-sin 30°:sin 60°=√3-1/2:√3/2=√3-1/2·2/√3 (simplificam 2 cu 2)=√3/1 (amplifici cu 3)-1/√3 (amplifici cu √3)=3√3/3-√3/3=2√3/3