1. Mca(oh)2=20+(16+1)x2=20+17x2=20+34=54
54g Ca(OH)2.....................16g O2
96g.......................................xg
x=96x16/54=28,44g O2
2. mC : mO= 3:8
Cx Oy
x=3/12=0,25/:0,25
=1/2 rezulta ca formula = CO2
y=8/16=0,5/:0,25
scuze daca nu am fost explicit dar e primul meu raspuns