m( ABC) =45°
m(CAB) =90°} =>m(ACB) =45°
m( (ABC) =45°
m( ACB) =45°.} => ∆ ABC isoscel
x- catetele congruente
In ∆ ABC dr. =>TP
AC²+CB²= AB²
x²+x²=14²
2x²=196
x²= 196:2
x²=98
x=√98
x=7√2
CA= CB =7√2
In ∆ ADC dr => AD²+CD²= AC²
AD²=(7√2)²-4²
AD²=98-16
AD² =82
AD=√82 cm