la primul inmultim prima relatie cu 2
4x+2y=10
3x-2y=4
le adunam
7x=14
x=2
y=(3x-4)/2=(6-4)/2=1
S=(1;2)
la al doilea
adunam a doua ecuatie cu a treia
4x=4
x=1
in locuim in prima
2*1+y-z=2
y-z=0
y=z
inlocuim ce am aflat deja in ultima
x+y+2y=4
1+3y=4
3y=3
y=1
z=y=1
S=(1;1;1)
as s1mple as that!!!
