4KMOL.......................................<4KMOL
C6H5-CH3+HONO2---> C6H4(NO2)-CH3 + H2O.
3KMOL........................................<3KMOL
C6H5-CH3+2HONO2---> C6H3(NO2)2-CH3+H2O
2KMOL.........................................<2KMOL
C6H5-CH3 +3HONO2---> C6H2(NO2)3-CH3
1KMOL
C6H5-CH3 nereactionat
total: 10kmol toluen
M,toluen= 92kg/kmol
M,dinitrotoluen= 182kg/kmol
n,dinitrotoluen= m/M= 546kg/182kg/kmol= 3kmol
din setul de reactii, se deduce ca 3kmol dinitrotoluen se obtine, in aceste conditii, din 10 kmol toluen, adica din: m= nxM= 10x92kg= 920kg
