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D={x€Z| 14 supra x+15 € Z}

Răspuns :

[tex] \frac{14}{x + 1} \: \in \: \mathbb{Z} = > x + 1 \: \in \: D_{14}[/tex]

[tex]D_{14} = \left \{ \pm1,\pm2,\pm7,\pm14 \right \}[/tex]

[tex]1)x + 1 = - 1 = > x = - 1 - 1 = - 2[/tex]

[tex] \frac{14}{ - 2 + 1} = \frac{14}{ - 1} = - \frac{14}{1} = - 14 \: \in \: \mathbb{Z}[/tex]

[tex]2)x + 1 = 1 = > x = 1 - 1 = 0[/tex]

[tex] \frac{14}{0 + 1} = \frac{14}{1} = 14 \: \in \: \mathbb{Z}[/tex]

[tex]3)x + 1 = - 2 = > x = - 2 - 1 = - 3[/tex]

[tex] \frac{14}{ - 3 + 1} = \frac{14}{ - 2} = - \frac{14}{2} = - 7 \: \in \: \mathbb{Z}[/tex]

[tex]4)x + 1 = 2 = > x = 2 - 1 = 1[/tex]

[tex] \frac{14}{1 + 1} = \frac{14}{2} = 7 \: \in \: \mathbb{Z}[/tex]

[tex]5)x + 1 = - 7 = > x = - 7 - 1 = - 8[/tex]

[tex] \frac{14}{ - 8 + 1} = \frac{14}{ - 7} = - \frac{14}{7} = - 2 \: \in \: \mathbb{Z}[/tex]

[tex]6)x + 1 = 7 = > x = 7 - 1 = 6[/tex]

[tex] \frac{14}{6 +1 } = \frac{14}{7} = 2 \: \in \: \mathbb{Z}[/tex]

[tex]7)x + 1 = - 14 = > x = - 14 - 1 = - 15[/tex]

[tex] \frac{14}{ - 15 + 1} = \frac{14}{ - 14} = - \frac{14}{14} = - 1 \: \in \: \mathbb{Z}[/tex]

[tex]8)x + 1 = 14 = > x = 14 - 1 = 13[/tex]

[tex] \frac{14}{13 + 1} = \frac{14}{14} = 1 \: \in \: \mathbb{Z}[/tex]