[tex] 1)\frac{2x + y}{3y} = \frac{2 \times 4y + y}{3y} = \frac{8y + y}{3y} = \frac{9y}{3y} {}^{(3y} = 3 \\ 2) \frac{x}{3} = y = > 3y\\ \frac{2y}{2y + x} = \frac{2y}{2y + 3y} = \frac{2y}{5y} = \frac{2}{5} \\ 3)x + y = 44 \\ \frac{x}{y} = \frac{3}{8} = k = > x = 3k \frac{}{} \frac{}{} y = 8k \\ 3k + 8k = 44 \\ 11k = 44 \\ k = 4 \\ x = 3k = 3 \times 4 = 12 \\ y \\ = 8k = 8 \times 4 = 32 \\ 4)x - y = 36 = > x = y + 36 \\ \frac{x}{y} = \frac{5}{7} = > x = 5k \frac{ {}^{} }{} y = 7k \\ 5k - 7k = 36 \\ - 2k = 36 \\ k = - 18 \\ x = 5k = 5 \times ( - 18) = -90 \\ y = 7k = 7 \times ( - 18) = - 126 \\ verificare \\ \: \: - 90 - ( - 126) = - 90 + 126 = 36 \\ 6) \: a) \: x = \frac{3}{5} = \frac{x + 6}{10} \\ 5(x + 6) = 3 \times 10 \\ 5x + 30 = 30 \\ 5x = 0 \\ x = 0 \\ b) \frac{2x + 1}{10} = \frac{3x + 1}{14} \\ 14(2x + 1) = 10(3x + 1) \\ 28 x+ 14 = 30x + 10 \\ 14 - 10 = 30x - 28x \\ 4 = 2x \\ x = 2[/tex]
coroana?
